3b^2=60

Solution for 3b^2=60 equation:

3b^2=60

We move all terms to the left:

3b^2-(60)=0

a = 3; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·3·(-60)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*3}=\frac{0-12\sqrt{5}}{6}
=-\frac{12\sqrt{5}}{6}
=-2\sqrt{5}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*3}=\frac{0+12\sqrt{5}}{6}
=\frac{12\sqrt{5}}{6}
=2\sqrt{5}
$